2500=x^(9/10)

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Solution for 2500=x^(9/10) equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

2500 = x^(9/10) // - x^(9/10)

2500-x^(9/10) = 0

-1*x^(9/10) = -2500 // : -1

x^(9/10) = 2500

( 2500 < 0 i 9/10 in (0:1) ) => x należy do O

x belongs to the empty set

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